Inequality(VintasoftRectI,VintasoftRectI) Оператор (VintasoftRectI)

В этом разделе

Tests whether two VintasoftRectI structures differ in location or size.

Синтаксис

'Declaration

Public Operator <>( _
   ByVal leftThe VintasoftRectI structure that is to the left of the inequality operator.
 As VintasoftRectI, _
   ByVal rightThe VintasoftRectI structure that is to the right of the inequality operator.
 As VintasoftRectI _
) As Boolean

public bool operator =(
   VintasoftRectI left, 
   VintasoftRectI right
)

public: bool op_Inequality(
   VintasoftRectI left, 
   VintasoftRectI right
)

public:
bool operator =(
   VintasoftRectI left, 
   VintasoftRectI right
)

Parameters

left: The VintasoftRectI structure that is to the left of the inequality operator.
right: The VintasoftRectI structure that is to the right of the inequality operator.

Return Value

True if any of the X , Y, Width, or Height properties of the two VintasoftRectI structures are unequal; otherwise, false.

Требования

Целевые платформы: .NET 10; .NET 9; .NET 8; .NET 7; .NET 6; .NET Framework 4.8, 4.7, 4.6, 4.5, 4.0, 3.5

Смотрите также

Справочник

VintasoftRectI Structure
Члены типа VintasoftRectI

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